Check whether the original sequence org can be uniquely reconstructed from the sequences in seqs. The org sequence is a permutation of the integers from 1 to n, with 1 ≤ n ≤ 104. Reconstruction means building a shortest common supersequence of the sequences in seqs (i.e., a shortest sequence so that all sequences in seqs are subsequences of it). Determine whether there is only one sequence that can be reconstructed from seqs and it is the org sequence.
Example 1:
Input:
org: [1,2,3], seqs: [[1,2],[1,3]]
Output:
false
Explanation:
[1,2,3] is not the only one sequence that can be reconstructed, because [1,3,2] is also a valid sequence that can be reconstructed.
Example 2:
Input:
org: [1,2,3], seqs: [[1,2]]
Output:
false
Explanation:
The reconstructed sequence can only be [1,2].
Example 3:
Input:
org: [1,2,3], seqs: [[1,2],[1,3],[2,3]]
Output:
true
Explanation:
The sequences [1,2], [1,3], and [2,3] can uniquely reconstruct the original sequence [1,2,3].
Example 4:
Input:
org: [4,1,5,2,6,3], seqs: [[5,2,6,3],[4,1,5,2]]
Output:
true
Solution
public class Solution {
public boolean sequenceReconstruction(int[] org, int[][] seqs) {
Map<Integer, Set<Integer>> edges = new HashMap<Integer, Set<Integer>>();
Map<Integer, Integer> indegree = new HashMap<Integer, Integer>();
for(int i = 0; i < seqs.length; i++) {
// processing seqs[i]
for(int j = 0; j < seqs[i].length; j++) {
if(!edges.containsKey(seqs[i][j]) ) edges.put(seqs[i][j], new HashSet<Integer>());
if(j < seqs[i].length - 1) {
if(edges.get(seqs[i][j]).add(seqs[i][j + 1])) {
if(!indegree.containsKey(seqs[i][j+1])) indegree.put(seqs[i][j+1],0);
indegree.put(seqs[i][j+1], indegree.get(seqs[i][j+1]) + 1);
}
}
}
}
Integer start = null;
// only one has a zero indegree
for(Integer key: edges.keySet()) {
if(!indegree.containsKey(key)) {
if(start == null) start = key;
else return false;
}
}
if(start == null) return false;
int idx = 0; // idx for org
while(idx < org.length) {
if(start == null || start != org[idx]) return false;
Set<Integer> next = edges.get(start);
start = null;
for(Integer dst: next) {
indegree.put(dst, indegree.get(dst)-1);
if(indegree.get(dst) == 0) {
if(start == null) start = dst;
else return false;
}
}
idx++;
}
// in case some edges are not covered
for(Integer key: indegree.keySet()) {
if(indegree.get(key) != 0) return false;
}
return start == null;
}
}