Serialization is the process of converting a data structure or object into a sequence of bits so that it can be stored in a file or memory buffer, or transmitted across a network connection link to be reconstructed later in the same or another computer environment.
Design an algorithm to serialize and deserialize a binary tree. There is no restriction on how your serialization/deserialization algorithm should work. You just need to ensure that a binary tree can be serialized to a string and this string can be deserialized to the original tree structure.
For example, you may serialize the following tree
1
/ \
2 3
/ \
4 5
as "[1,2,3,null,null,4,5]", just the same as how LeetCode OJ serializes a binary tree. You do not necessarily need to follow this format, so please be creative and come up with different approaches yourself. Note: Do not use class member/global/static variables to store states. Your serialize and deserialize algorithms should be stateless.
Solution
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
public class Codec {
// Encodes a tree to a single string.
public String serialize(TreeNode root) {
if(root == null) return "null";
StringBuilder sb = new StringBuilder();
Queue<TreeNode> queue = new LinkedList<TreeNode>();
Queue<TreeNode> next = new LinkedList<TreeNode>();
queue.offer(root);
sb.append(root.val);
while(!queue.isEmpty()) {
// every good father will have their children serialize
while(!queue.isEmpty()) {
TreeNode node = queue.poll();
if(node != null) {
// serialize its children
sb.append("," + (node.left == null ? "n" : node.left.val));
sb.append("," + (node.right == null ? "n" : node.right.val));
if(node.left != null) next.offer(node.left);
if(node.right != null) next.offer(node.right);
}
}
Queue tmp = queue; queue = next; next = tmp;
}
return sb.toString();
}
// Decodes your encoded data to tree.
public TreeNode deserialize(String data) {
if(data == null || data.equals("null")) return null;
String[] nodes = data.split(",");
TreeNode root = new TreeNode(Integer.valueOf(nodes[0]));
List<TreeNode> list = new ArrayList<TreeNode>();
list.add(root);
int listIdx = 0;
int i = 1;
while(i < nodes.length) {
if(!nodes[i].equals("n")) list.get(listIdx).left = new TreeNode(Integer.valueOf(nodes[i]));
if(!nodes[i+1].equals("n")) list.get(listIdx).right = new TreeNode(Integer.valueOf(nodes[i+1]));
i += 2;
listIdx++;
if(listIdx == list.size()) {
List<TreeNode> nlist = new ArrayList<TreeNode>();
for(TreeNode node: list) {
if(node.left != null) nlist.add(node.left);
if(node.right != null) nlist.add(node.right);
}
list = nlist;
listIdx = 0;
}
}
return root;
}
}
// Your Codec object will be instantiated and called as such:
// Codec codec = new Codec();
// codec.deserialize(codec.serialize(root));